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Popular >

solvefor a,2^a=7^b

Solution

solve for

a, 2^{a} = 7^{b}

Solution

a = \frac{b ln ( 7 )}{ln ( 2 )}

Solution steps

2^{a} = 7^{b}

Apply exponent rules

a ln (2) = b ln (7)

Solve

a ln (2) = b ln (7) : a = \frac{b ln ( 7 )}{ln ( 2 )}

a = \frac{b ln ( 7 )}{ln ( 2 )}

Popular Examples

5^{x-3}*3^{2x}-8=225

5^{x - 3} \cdot 3^{2 x} - 8 = 225

5(3^{2x-1})=243

5 (3^{2 x - 1}) = 243

3^{2x}-6*3^{x+1}-243=0

3^{2 x} - 6 \cdot 3^{x + 1} - 243 = 0

((2x^7))/((1-x))=30

\frac{( 2 x ^{7} )}{( 1 - x )} = 30

solvefor x,x^2+(y-4/(x^2))2=1 solve for

x, x^{2} + (y - \frac{4}{x ^{2}}) 2 = 1

Frequently Asked Questions (FAQ)

What is the answer to solvefor a,2^a=7^b ?
The answer to solvefor a,2^a=7^b is a=(bln(7))/(ln(2))