What is the answer to 2((x^2+1}{(x^2)})-3(\frac{x-1)/x)-4=0 ?

The answer to 2((x^2+1}{(x^2)})-3(\frac{x-1)/x)-4=0 is x=-2/5 ,x=1

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2((x^2+1}{(x^2)})-3(\frac{x-1)/x)-4=0

2 (\frac{x ^{2} + 1}{( x ^{2} )}) - 3 (\frac{x - 1}{x}) - 4 = 0

x = - \frac{2}{5}, x = 1

Decimal Notation

x = - 0.4, x = 1

Solution steps

2 (\frac{x ^{2} + 1}{( x ^{2} )}) - 3 (\frac{x - 1}{x}) - 4 = 0

Multiply by LCM

2 (x^{2} + 1) - 3 x (x - 1) - 4 x^{2} = 0

Solve

2 (x^{2} + 1) - 3 x (x - 1) - 4 x^{2} = 0 : x = - \frac{2}{5}, x = 1

x = - \frac{2}{5}, x = 1

Verify Solutions

Find undefined (singularity) points:

x = 0

Combine undefined points with solutions:

x = - \frac{2}{5}, x = 1

\frac{( 2 ^{n} + 2 ^{n - 1} )}{( 2 ^{n + 1} - 2 ^{n} )} = \frac{3}{2}

\frac{31}{2 x} = 56

\frac{2}{( 3 x )} + \frac{( 2 x - 1 )}{( 4 x ^{2} )} = \frac{5}{( 12 x )}

\frac{1}{x} = \frac{1}{a} + \frac{1}{b}

\frac{6}{- x} = \frac{x}{- 24}

What is the answer to 2((x^2+1}{(x^2)})-3(\frac{x-1)/x)-4=0 ?
The answer to 2((x^2+1}{(x^2)})-3(\frac{x-1)/x)-4=0 is x=-2/5 ,x=1
Solve for x: 2((x^2+1}{(x^2)})-3(\frac{x-1)/x)-4=0
The solution is x=-2/5 ,x=1