What is the answer to x^{-4}=16 ?

The answer to x^{-4}=16 is x= 1/2 ,x=-1/2 ,x= 1/2 i,x=-1/2 i

Solve for x: x^{-4}=16

The solution is x= 1/2 ,x=-1/2 ,x= 1/2 i,x=-1/2 i

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x^{- 4} = 16

x = \frac{1}{2}, x = - \frac{1}{2}, x = \frac{1}{2} i, x = - \frac{1}{2} i

Solution steps

x^{- 4} = 16

Refine

\frac{1}{x ^{4}} = 16

Multiply both sides by

x^{4}

1 = 16 x^{4}

Solve

1 = 16 x^{4} : x = \frac{1}{2}, x = - \frac{1}{2}, x = \frac{1}{2} i, x = - \frac{1}{2} i

x = \frac{1}{2}, x = - \frac{1}{2}, x = \frac{1}{2} i, x = - \frac{1}{2} i

Verify Solutions

Find undefined (singularity) points:

x = 0

Combine undefined points with solutions:

x = \frac{1}{2}, x = - \frac{1}{2}, x = \frac{1}{2} i, x = - \frac{1}{2} i

\frac{n ^{2}}{y ^{2}} + \frac{y ^{2}}{n ^{2}} = 223

x, \frac{2}{x} + \frac{3}{y} = 1

\frac{x}{( x ^{2} + 1 )} + \frac{( x ^{2} + 1 )}{x} = \frac{5}{2}

\frac{x}{( x - 1 )} + \frac{( x - 1 )}{x} = \frac{21}{2}

\frac{2}{( x - 3 )} + \frac{1}{( x - 1 )} = \frac{5}{( x - 1 )} - \frac{2}{( x - 2 )}

What is the answer to x^{-4}=16 ?
The answer to x^{-4}=16 is x= 1/2 ,x=-1/2 ,x= 1/2 i,x=-1/2 i
Solve for x: x^{-4}=16
The solution is x= 1/2 ,x=-1/2 ,x= 1/2 i,x=-1/2 i