What is the answer to 1/(7*x^2+1)= 4/(7*x) ?

The answer to 1/(7*x^2+1)= 4/(7*x) is x= 1/8+i(sqrt(399))/(56),x= 1/8-i(sqrt(399))/(56)

Solve for x: 1/(7*x^2+1)= 4/(7*x)

The solution is x= 1/8+i(sqrt(399))/(56),x= 1/8-i(sqrt(399))/(56)

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\frac{1}{7 \cdot x ^{2} + 1} = \frac{4}{7 \cdot x}

x = \frac{1}{8} + i \frac{399}{56}, x = \frac{1}{8} - i \frac{399}{56}

Solution steps

\frac{1}{7 x ^{2} + 1} = \frac{4}{7 x}

Cross multiply

7 x = (7 x^{2} + 1) \cdot 4

Solve

7 x = (7 x^{2} + 1) \cdot 4 : x = \frac{1}{8} + i \frac{399}{56}, x = \frac{1}{8} - i \frac{399}{56}

x = \frac{1}{8} + i \frac{399}{56}, x = \frac{1}{8} - i \frac{399}{56}

x, 3 y = \frac{( 7 w )}{x}

\frac{7 x - 3 + 32}{3 \cdot x - 1} = \frac{1}{3}

\frac{2.5 x + 2}{5} = \frac{4}{5 - 3.5 x}

\frac{9}{2 x} = 5 + x^{2}

\frac{x ^{2} - 1}{3} = \frac{1}{6 x ^{2}}

What is the answer to 1/(7*x^2+1)= 4/(7*x) ?
The answer to 1/(7*x^2+1)= 4/(7*x) is x= 1/8+i(sqrt(399))/(56),x= 1/8-i(sqrt(399))/(56)
Solve for x: 1/(7*x^2+1)= 4/(7*x)
The solution is x= 1/8+i(sqrt(399))/(56),x= 1/8-i(sqrt(399))/(56)