What is the answer to p=((y+2b))/y ?

The answer to p=((y+2b))/y is y=(2b)/(p-1);\quad p\ne 1

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p=((y+2b))/y

p = \frac{( y + 2 b )}{y}

y = \frac{2 b}{p - 1}; p \neq = 1

Solution steps

p = \frac{( y + 2 b )}{y}

Simplify

\frac{( y + 2 b )}{y} : \frac{y + 2 b}{y}

p = \frac{y + 2 b}{y}

Multiply both sides by

y

p y = y + 2 b

Move

y

to the left side

p y - y = 2 b

Factor

p y - y : y (p - 1)

y (p - 1) = 2 b

Divide both sides by

p - 1; p \neq = 1

y = \frac{2 b}{p - 1}; p \neq = 1

\frac{( 3 x - 5 )}{( x + 5 )} = 1

\frac{( n + 3 ) !}{( n + 1 ) !} = 30

n, v = (\frac{1}{n}) \frac{r ^{2}}{3} s \frac{1}{2}

x = \frac{4}{5 \cdot ( x + 10 )}

g = \frac{9.8 m}{s ^{2}}

What is the answer to p=((y+2b))/y ?
The answer to p=((y+2b))/y is y=(2b)/(p-1);\quad p\ne 1