What is the answer to 1/((2a+b+2x))= 1/((2a))+1/b+1/((2x)) ?

The answer to 1/((2a+b+2x))= 1/((2a))+1/b+1/((2x)) is x=-b/2 ,x=-a;\quad 4a+2b\ne 0

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1/((2a+b+2x))= 1/((2a))+1/b+1/((2x))

\frac{1}{( 2 a + b + 2 x )} = \frac{1}{( 2 a )} + \frac{1}{b} + \frac{1}{( 2 x )}

x = - \frac{b}{2}, x = - a; 4 a + 2 b \neq = 0

Solution steps

\frac{1}{( 2 a + b + 2 x )} = \frac{1}{( 2 a )} + \frac{1}{b} + \frac{1}{( 2 x )}

Multiply by LCM

2 ab x = b x (2 x + 2 a + b) + 2 a x (2 x + 2 a + b) + ab (2 x + 2 a + b)

Solve

2 ab x = b x (2 x + 2 a + b) + 2 a x (2 x + 2 a + b) + ab (2 x + 2 a + b) : x = - \frac{b}{2}, x = - a; 4 a + 2 b \neq = 0

x = - \frac{b}{2}, x = - a; 4 a + 2 b \neq = 0

a, (p + 4) - 2 \frac{p}{a} = 8

\frac{12}{( 0.1 + x ) - 20} = \frac{12}{( 0.2 + x )}

x^{2} + \frac{1}{x ^{2}} + 5 x - \frac{5}{x} + 4 = 0

\frac{- 1}{2 + 3 ( \frac{1}{2} - 2 x )} = - \frac{3}{2}

\frac{3}{7 d} = 21

What is the answer to 1/((2a+b+2x))= 1/((2a))+1/b+1/((2x)) ?
The answer to 1/((2a+b+2x))= 1/((2a))+1/b+1/((2x)) is x=-b/2 ,x=-a;\quad 4a+2b\ne 0