What is the answer to 4/x+3/((x^2+x))=0 ?

The answer to 4/x+3/((x^2+x))=0 is x=-7/4

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4/x+3/((x^2+x))=0

\frac{4}{x} + \frac{3}{( x ^{2} + x )} = 0

x = - \frac{7}{4}

Decimal Notation

x = - 1.75

Solution steps

\frac{4}{x} + \frac{3}{( x ^{2} + x )} = 0

Multiply by LCM

4 (x + 1) + 3 = 0

Move

3

to the right side

4 (x + 1) = - 3

Divide both sides by

4

x + 1 = - \frac{3}{4}

Move

1

to the right side

x = - \frac{7}{4}

Verify Solutions

Find undefined (singularity) points:

x = 0, x = - 1

Combine undefined points with solutions:

x = - \frac{7}{4}

\frac{x}{3} + \frac{3}{x} = \frac{41}{4}

\frac{( x ^{2} - 2 x ) ( 2 x - 2 ) - 9 ( 2 x - 2 )}{( x ^{2} - 2 x )} = 0

x, \frac{4}{x} - \frac{5}{y} = 2

\frac{51}{2 - 3 x} = \frac{4}{3}

\frac{2 ( x + 3 )}{5 x - 2} = \frac{- 3}{5}

What is the answer to 4/x+3/((x^2+x))=0 ?
The answer to 4/x+3/((x^2+x))=0 is x=-7/4
Solve for x: 4/x+3/((x^2+x))=0
The solution is x=-7/4