What is the answer to a-b=(a+1)/(ax) ?

The answer to a-b=(a+1)/(ax) is x=(a+1)/(a(a-b));\quad a\ne b

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a-b=(a+1)/(ax)

a - b = \frac{a + 1}{a x}

x = \frac{a + 1}{a ( a - b )}; a \neq = b

Solution steps

a - b = \frac{a + 1}{a x}

Multiply both sides by

x

a x - b x = \frac{a + 1}{a}

Expand

\frac{a + 1}{a} : 1 + \frac{1}{a}

a x - b x = 1 + \frac{1}{a}

Factor

a x - b x : x (a - b)

x (a - b) = 1 + \frac{1}{a}

Divide both sides by

a - b; a \neq = b

x = \frac{a + 1}{a ( a - b )}; a \neq = b

x^{2} - 1 = \frac{1}{3 ( x + 3 )}

\frac{( x - 4.8 )}{x} = 0.18

(\frac{( x + 1 )}{( x + 2 )})^{2} = \frac{( x + 2 )}{( x + 4 )}

\frac{( x - 2 )}{( x + 2 )} + \frac{( x + 2 )}{( x - 2 )} = 4

\frac{9.99 - 0.99}{( 99 y - 9.9 )} = 9.09

What is the answer to a-b=(a+1)/(ax) ?
The answer to a-b=(a+1)/(ax) is x=(a+1)/(a(a-b));\quad a\ne b