What is the answer to 2((x+1)/x)^2-3((x-1)/x)-8=0 ?

The answer to 2((x+1)/x)^2-3((x-1)/x)-8=0 is x=-2/9 ,x=1

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2((x+1)/x)^2-3((x-1)/x)-8=0

2 (\frac{x + 1}{x})^{2} - 3 (\frac{x - 1}{x}) - 8 = 0

x = - \frac{2}{9}, x = 1

Decimal Notation

x = - 0.22222 \dots, x = 1

Solution steps

2 (\frac{x + 1}{x})^{2} - 3 (\frac{x - 1}{x}) - 8 = 0

Multiply by LCM

2 (x + 1)^{2} - 3 x (x - 1) - 8 x^{2} = 0

Solve

2 (x + 1)^{2} - 3 x (x - 1) - 8 x^{2} = 0 : x = - \frac{2}{9}, x = 1

x = - \frac{2}{9}, x = 1

Verify Solutions

Find undefined (singularity) points:

x = 0

Combine undefined points with solutions:

x = - \frac{2}{9}, x = 1

\frac{1}{( x - 2 )} + \frac{1}{( x + 3 )} + \frac{1}{( x + 4 )} = 0

\frac{1.1}{3} = \frac{4}{x}

\frac{t}{( t + 3 )} = \frac{11}{5}

x, x + \frac{y}{x} - y = 12

\frac{x + 1}{x} = \frac{21}{2}

What is the answer to 2((x+1)/x)^2-3((x-1)/x)-8=0 ?
The answer to 2((x+1)/x)^2-3((x-1)/x)-8=0 is x=-2/9 ,x=1
Solve for x: 2((x+1)/x)^2-3((x-1)/x)-8=0
The solution is x=-2/9 ,x=1