What is the answer to ((5^{4y-1}))/((25^y))=((125^{y+3}))/((25^{2-y))} ?

The answer to ((5^{4y-1}))/((25^y))=((125^{y+3}))/((25^{2-y))} is y=-2

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((5^{4y-1}))/((25^y))=((125^{y+3}))/((25^{2-y))}

\frac{( 5 ^{4 y - 1} )}{( 2 5 ^{y} )} = \frac{( 12 5 ^{y + 3} )}{( 2 5 ^{2 - y} )}

y = - 2

Solution steps

\frac{( 5 ^{4 y - 1} )}{( 2 5 ^{y} )} = \frac{( 12 5 ^{y + 3} )}{( 2 5 ^{2 - y} )}

Simplify

5^{2 y - 1} = 5^{5 y + 5}

Solve

5^{2 y - 1} = 5^{5 y + 5} : y = - 2

y = - 2

(\frac{x ^{2} + 1}{( x ^{2} )}) - 5 (\frac{x + 1}{x}) + 6 = 0

1.87 = \frac{( 1 - 2 p ) ^{2}}{( ( 1 + p ) \cdot ( 2 p ) ^{2} )}

\frac{1}{3 + x} = \frac{5 + x}{6}

ln (9) = \frac{- 36 \cdot 1 0 ^{10}}{x}

\frac{y - 1}{3 y} = 4

What is the answer to ((5^{4y-1}))/((25^y))=((125^{y+3}))/((25^{2-y))} ?
The answer to ((5^{4y-1}))/((25^y))=((125^{y+3}))/((25^{2-y))} is y=-2
Solve for y: ((5^{4y-1}))/((25^y))=((125^{y+3}))/((25^{2-y))}
The solution is y=-2