What is the answer to 1/(2x(3/4+x))=-7/10 ?

The answer to 1/(2x(3/4+x))=-7/10 is x=-3/8-i(sqrt(1799))/(56),x=-3/8+i(sqrt(1799))/(56)

Solve for x: 1/(2x(3/4+x))=-7/10

The solution is x=-3/8-i(sqrt(1799))/(56),x=-3/8+i(sqrt(1799))/(56)

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\frac{1}{2 x ( \frac{3}{4} + x )} = - \frac{7}{10}

x = - \frac{3}{8} - i \frac{1799}{56}, x = - \frac{3}{8} + i \frac{1799}{56}

Solution steps

\frac{1}{2 x ( \frac{3}{4} + x )} = - \frac{7}{10}

Cross multiply

20 = - x (4 x + 3) \cdot 7

Solve

20 = - x (4 x + 3) \cdot 7 : x = - \frac{3}{8} - i \frac{1799}{56}, x = - \frac{3}{8} + i \frac{1799}{56}

x = - \frac{3}{8} - i \frac{1799}{56}, x = - \frac{3}{8} + i \frac{1799}{56}

\frac{( m ^{2} - ( m + 1 ) ( m + 5 ) )}{( 2 m + 1 )} = 10

\frac{x ^{4} + 9}{6 x ^{2}} = \frac{5}{3}

\frac{n}{s} = 60

\frac{x ^{2}}{x} = 6

\frac{x + 1}{x} = \frac{31}{3}

What is the answer to 1/(2x(3/4+x))=-7/10 ?
The answer to 1/(2x(3/4+x))=-7/10 is x=-3/8-i(sqrt(1799))/(56),x=-3/8+i(sqrt(1799))/(56)
Solve for x: 1/(2x(3/4+x))=-7/10
The solution is x=-3/8-i(sqrt(1799))/(56),x=-3/8+i(sqrt(1799))/(56)