What is the answer to 4((x^2+1}{(x^2)})-8(\frac{x+1)/x)+3=0 ?

The answer to 4((x^2+1}{(x^2)})-8(\frac{x+1)/x)+3=0 is x=-2(2+sqrt(5)),x=2(sqrt(5)-2)

Solve for x: 4((x^2+1}{(x^2)})-8(\frac{x+1)/x)+3=0

The solution is x=-2(2+sqrt(5)),x=2(sqrt(5)-2)

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4 (\frac{x ^{2} + 1}{( x ^{2} )}) - 8 (\frac{x + 1}{x}) + 3 = 0

x = - 2 (2 + 5), x = 2 (5 - 2)

Decimal Notation

x = - 8.47213 \dots, x = 0.47213 \dots

Solution steps

4 (\frac{x ^{2} + 1}{( x ^{2} )}) - 8 (\frac{x + 1}{x}) + 3 = 0

Multiply by LCM

4 (x^{2} + 1) - 8 x (x + 1) + 3 x^{2} = 0

Solve

4 (x^{2} + 1) - 8 x (x + 1) + 3 x^{2} = 0 : x = - 2 (2 + 5), x = 2 (5 - 2)

x = - 2 (2 + 5), x = 2 (5 - 2)

Verify Solutions

Find undefined (singularity) points:

x = 0

Combine undefined points with solutions:

x = - 2 (2 + 5), x = 2 (5 - 2)

(\frac{34.56}{1000}) = (\frac{18}{x})

\frac{y}{0.25 + y + 0.5} = 9

\frac{\frac{21}{3}}{x} = \frac{\frac{8}{9}}{4}

\frac{x}{12 x + 4 x} = 48

x, f (x + 1) - f = \frac{1}{x}

What is the answer to 4((x^2+1}{(x^2)})-8(\frac{x+1)/x)+3=0 ?
The answer to 4((x^2+1}{(x^2)})-8(\frac{x+1)/x)+3=0 is x=-2(2+sqrt(5)),x=2(sqrt(5)-2)
Solve for x: 4((x^2+1}{(x^2)})-8(\frac{x+1)/x)+3=0
The solution is x=-2(2+sqrt(5)),x=2(sqrt(5)-2)