What is the answer to (x^2+1)/(2x)=2 ?

The answer to (x^2+1)/(2x)=2 is x=2+sqrt(3),x=2-sqrt(3)

Solve for x: (x^2+1)/(2x)=2

The solution is x=2+sqrt(3),x=2-sqrt(3)

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\frac{x ^{2} + 1}{2 x} = 2

x = 2 + 3, x = 2 - 3

Decimal Notation

x = 3.73205 \dots, x = 0.26794 \dots

Solution steps

\frac{x ^{2} + 1}{2 x} = 2

Multiply both sides by

x

\frac{x ^{2} + 1}{2} = 2 x

Solve

\frac{x ^{2} + 1}{2} = 2 x : x = 2 + 3, x = 2 - 3

x = 2 + 3, x = 2 - 3

Verify Solutions

Find undefined (singularity) points:

x = 0

Combine undefined points with solutions:

x = 2 + 3, x = 2 - 3

\frac{x}{6} - \frac{3}{x} = \frac{1}{2}

\frac{x}{2 + 2 x} = x + 3

\frac{4}{( ∣ x + 1 ∣ - 2 )} = ∣ x + 1 ∣

a = \frac{2 m}{s ^{2}}

\frac{1}{( x ^{2} - 10 x - 29 )} + \frac{1}{( x ^{2} - 10 x - 45 )} - \frac{2}{( x ^{2} - 10 x - 69 )} = 0

What is the answer to (x^2+1)/(2x)=2 ?
The answer to (x^2+1)/(2x)=2 is x=2+sqrt(3),x=2-sqrt(3)
Solve for x: (x^2+1)/(2x)=2
The solution is x=2+sqrt(3),x=2-sqrt(3)