What is the answer to solvefor a, 1/a+2/b = 1/3 ?

The answer to solvefor a, 1/a+2/b = 1/3 is a=-(3b)/(6-b);\quad b\ne 6

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solvefor a, 1/a+2/b = 1/3

solve for

a, \frac{1}{a} + \frac{2}{b} = \frac{1}{3}

a = - \frac{3 b}{6 - b}; b \neq = 6

Solution steps

\frac{1}{a} + \frac{2}{b} = \frac{1}{3}

Multiply by LCM

3 b + 6 a = ab

Move

3 b

to the right side

6 a = ab - 3 b

Move

ab

to the left side

6 a - ab = - 3 b

Factor

6 a - ab : a (6 - b)

a (6 - b) = - 3 b

Divide both sides by

6 - b; b \neq = 6

a = - \frac{3 b}{6 - b}; b \neq = 6

\frac{1.2}{43} = \frac{4.8}{x}

\frac{( 2 + x ) ( x - 7 )}{( x - 5 ) ( x + 4 )} = 1

4 \frac{x ^{2}}{x} - 1 - 1 - 3 \frac{x}{4} = 20 \frac{x}{3}

\frac{x ^{2} + x ^{2}}{( x + 1 ) ^{2}} = 3

\frac{3}{7 + x} = \frac{17}{7}

What is the answer to solvefor a, 1/a+2/b = 1/3 ?
The answer to solvefor a, 1/a+2/b = 1/3 is a=-(3b)/(6-b);\quad b\ne 6