What is the answer to x+1/x =5,x^2+1/((x^2))=,x^3+1/((x^3)) ?

The answer to x+1/x =5,x^2+1/((x^2))=,x^3+1/((x^3)) is x=(5+sqrt(21))/2 ,x=(5-sqrt(21))/2

Solve for x: x+1/x =5,x^2+1/((x^2))=,x^3+1/((x^3))

The solution is x=(5+sqrt(21))/2 ,x=(5-sqrt(21))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x + \frac{1}{x} = 5, x^{2} + \frac{1}{( x ^{2} )} =, x^{3} + \frac{1}{( x ^{3} )}

x = \frac{5 + 21}{2}, x = \frac{5 - 21}{2}

Decimal Notation

x = 4.79128 \dots, x = 0.20871 \dots

Solution steps

x + \frac{1}{x} = 5

Multiply both sides by

x

x^{2} + 1 = 5 x

Solve

x^{2} + 1 = 5 x : x = \frac{5 + 21}{2}, x = \frac{5 - 21}{2}

x = \frac{5 + 21}{2}, x = \frac{5 - 21}{2}

Verify Solutions

Find undefined (singularity) points:

x = 0

Combine undefined points with solutions:

x = \frac{5 + 21}{2}, x = \frac{5 - 21}{2}

\frac{x - 1}{4} = \frac{1}{4 - x}

\frac{( 5 + x )}{( 100 + x )} = 0.24

\frac{x}{2 ^{2 x + 3}} = 8^{5 + x}

∣ x ∣ + \frac{( 4 - x ^{2} )}{x} = \frac{4}{x}

7 = \frac{31}{7 + 4 g}

What is the answer to x+1/x =5,x^2+1/((x^2))=,x^3+1/((x^3)) ?
The answer to x+1/x =5,x^2+1/((x^2))=,x^3+1/((x^3)) is x=(5+sqrt(21))/2 ,x=(5-sqrt(21))/2
Solve for x: x+1/x =5,x^2+1/((x^2))=,x^3+1/((x^3))
The solution is x=(5+sqrt(21))/2 ,x=(5-sqrt(21))/2