What are the solutions to the equation 9x^2+12x+4=0 ?

The solutions to the equation 9x^2+12x+4=0 are x=-2/3

Find the zeros of 9x^2+12x+4=0

The zeros of 9x^2+12x+4=0 are x=-2/3

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9 x^{2} + 12 x + 4 = 0

x = - \frac{2}{3}

Solution steps

9 x^{2} + 12 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 9 \cdot 4}{2 \cdot 9}

1 2^{2} - 4 \cdot 9 \cdot 4 = 0

x_{1, 2} = \frac{- 12 \pm 0}{2 \cdot 9}

x = \frac{- 12}{2 \cdot 9}

\frac{- 12}{2 \cdot 9} = - \frac{2}{3}

x = - \frac{2}{3}

The solution to the quadratic equation is:

x = - \frac{2}{3}

2 x^{2} - 8 x + 4 = 0

- 3 ∣ p ∣ = - 12

- 4 x - 14 - 9 x = - 13 x - 7 - 6

60 x^{3} + 50 x^{5}

(27) \frac{4}{3}

What are the solutions to the equation 9x^2+12x+4=0 ?
The solutions to the equation 9x^2+12x+4=0 are x=-2/3
Find the zeros of 9x^2+12x+4=0
The zeros of 9x^2+12x+4=0 are x=-2/3