What is the answer to (x^2+1)/(x^2)=(x^4+1)/(x^4) ?

The answer to (x^2+1)/(x^2)=(x^4+1)/(x^4) is x=-1,x=1

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(x^2+1)/(x^2)=(x^4+1)/(x^4)

\frac{x ^{2} + 1}{x ^{2}} = \frac{x ^{4} + 1}{x ^{4}}

x = - 1, x = 1

Solution steps

\frac{x ^{2} + 1}{x ^{2}} = \frac{x ^{4} + 1}{x ^{4}}

Cross multiply

(x^{2} + 1) x^{4} = x^{2} (x^{4} + 1)

Solve

(x^{2} + 1) x^{4} = x^{2} (x^{4} + 1) : x = 0, x = - 1, x = 1

x = 0, x = - 1, x = 1

Verify Solutions

Find undefined (singularity) points:

x = 0

Since the equation is undefined for:

0

x = - 1, x = 1

\frac{1}{m} + n + x = \frac{1}{m} + \frac{1}{n} + \frac{1}{x}

a^{- m} = \frac{1}{a ^{m}}

\frac{3 x + 9}{2} = \frac{2}{3 x + 5}

\frac{31}{4 x} = 1300000

\frac{4 x ^{2}}{( x - 3 )} = \frac{4 x ^{2}}{( x - 3 )}

What is the answer to (x^2+1)/(x^2)=(x^4+1)/(x^4) ?
The answer to (x^2+1)/(x^2)=(x^4+1)/(x^4) is x=-1,x=1
Solve for x: (x^2+1)/(x^2)=(x^4+1)/(x^4)
The solution is x=-1,x=1