What is the answer to (x^{2002}+4x^{2001})/(4x^{2000)}=7 ?

The answer to (x^{2002}+4x^{2001})/(4x^{2000)}=7 is x=2(2sqrt(2)-1),x=-2(1+2sqrt(2))

Solve for x: (x^{2002}+4x^{2001})/(4x^{2000)}=7

The solution is x=2(2sqrt(2)-1),x=-2(1+2sqrt(2))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{x ^{2002} + 4 x ^{2001}}{4 x ^{2000}} = 7

x = 2 (22 - 1), x = - 2 (1 + 22)

Decimal Notation

x = 3.65685 \dots, x = - 7.65685 \dots

Solution steps

\frac{x ^{2002} + 4 x ^{2001}}{4 x ^{2000}} = 7

Simplify

\frac{x ^{2002} + 4 x ^{2001}}{4 x ^{2000}} : \frac{x ( x + 4 )}{4}

\frac{x ( x + 4 )}{4} = 7

Multiply both sides by

4

x (x + 4) = 28

Solve

x (x + 4) = 28 : x = 2 (22 - 1), x = - 2 (1 + 22)

x = 2 (22 - 1), x = - 2 (1 + 22)

Verify Solutions

Find undefined (singularity) points:

x = 0

Combine undefined points with solutions:

x = 2 (22 - 1), x = - 2 (1 + 22)

x, \frac{( 2 )}{( w )} = \frac{( 3 )}{( y )} - \frac{( 1 )}{( x )}

\frac{4 ^{12}}{4 ^{10} - x} = 7

3 + 22 = \frac{x + 1}{x}

\frac{2 - x}{5 + 3 x} = \frac{12 + 1}{2}

3.067 = \frac{1.85}{v} + \frac{v ^{2}}{2} \cdot 9.81

What is the answer to (x^{2002}+4x^{2001})/(4x^{2000)}=7 ?
The answer to (x^{2002}+4x^{2001})/(4x^{2000)}=7 is x=2(2sqrt(2)-1),x=-2(1+2sqrt(2))
Solve for x: (x^{2002}+4x^{2001})/(4x^{2000)}=7
The solution is x=2(2sqrt(2)-1),x=-2(1+2sqrt(2))