What is the answer to (x^3-1)/(8x)=0 ?

The answer to (x^3-1)/(8x)=0 is x=1,x=-1/2+(sqrt(3))/2 i,x=-1/2-(sqrt(3))/2 i

Solve for x: (x^3-1)/(8x)=0

The solution is x=1,x=-1/2+(sqrt(3))/2 i,x=-1/2-(sqrt(3))/2 i

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\frac{x ^{3} - 1}{8 x} = 0

x = 1, x = - \frac{1}{2} + \frac{3}{2} i, x = - \frac{1}{2} - \frac{3}{2} i

Solution steps

\frac{x ^{3} - 1}{8 x} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

x^{3} - 1 = 0

Solve

x^{3} - 1 = 0 : x = 1, x = - \frac{1}{2} + \frac{3}{2} i, x = - \frac{1}{2} - \frac{3}{2} i

x = 1, x = - \frac{1}{2} + \frac{3}{2} i, x = - \frac{1}{2} - \frac{3}{2} i

Verify Solutions

Find undefined (singularity) points:

x = 0

Combine undefined points with solutions:

x = 1, x = - \frac{1}{2} + \frac{3}{2} i, x = - \frac{1}{2} - \frac{3}{2} i

\frac{21}{3 x - 7} = 25

x = \frac{2 + 3 x ^{4} + 1}{( x ^{4} )}

\frac{x \cdot ( x ^{6} - 1 )}{( x ^{8} + 1 )} = \frac{8}{17}

x - \frac{6}{3} x + 1 - x + \frac{6}{3} x - 1 = 3 x + \frac{2}{( x - 1 )} (x + 3)

50 = \frac{0.0023}{x}

What is the answer to (x^3-1)/(8x)=0 ?
The answer to (x^3-1)/(8x)=0 is x=1,x=-1/2+(sqrt(3))/2 i,x=-1/2-(sqrt(3))/2 i
Solve for x: (x^3-1)/(8x)=0
The solution is x=1,x=-1/2+(sqrt(3))/2 i,x=-1/2-(sqrt(3))/2 i