What is the answer to (1)2*((x+1)/x)^2-3((x-1)/x)-8=0 ?

The answer to (1)2*((x+1)/x)^2-3((x-1)/x)-8=0 is x=-2/9 ,x=1

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(1)2*((x+1)/x)^2-3((x-1)/x)-8=0

(1) 2 \cdot (\frac{x + 1}{x})^{2} - 3 (\frac{x - 1}{x}) - 8 = 0

x = - \frac{2}{9}, x = 1

Decimal Notation

x = - 0.22222 \dots, x = 1

Solution steps

(1) \cdot 2 (\frac{x + 1}{x})^{2} - 3 (\frac{x - 1}{x}) - 8 = 0

Multiply by LCM

2 (x + 1)^{2} - 3 x (x - 1) - 8 x^{2} = 0

Solve

2 (x + 1)^{2} - 3 x (x - 1) - 8 x^{2} = 0 : x = - \frac{2}{9}, x = 1

x = - \frac{2}{9}, x = 1

Verify Solutions

Find undefined (singularity) points:

x = 0

Combine undefined points with solutions:

x = - \frac{2}{9}, x = 1

\frac{x}{3 \cdot x} = 9^{2}

\frac{3}{( x - 2 )} + \frac{4}{( x + 2 )} = \frac{( 7 x - 2 )}{( x ^{2} - 4 )}

\frac{( 2.5 x + 4 )}{( 1.2 x + 8 )} = \frac{5}{4}

\frac{8}{6 x + 12} = \frac{- 11}{7 x - 10}

0.5 = \frac{2}{x}

What is the answer to (1)2*((x+1)/x)^2-3((x-1)/x)-8=0 ?
The answer to (1)2*((x+1)/x)^2-3((x-1)/x)-8=0 is x=-2/9 ,x=1
Solve for x: (1)2*((x+1)/x)^2-3((x-1)/x)-8=0
The solution is x=-2/9 ,x=1