What is the answer to 0.0177=(log_{10}(0.29))/((a-x)) ?

The answer to 0.0177=(log_{10}(0.29))/((a-x)) is x=-(log_{10}(0.29)-0.0177a)/(0.0177)

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0.0177=(log_{10}(0.29))/((a-x))

0.0177 = \frac{lo g _{10} ( 0.29 )}{( a - x )}

x = - \frac{lo g _{10} ( 0.29 ) - 0.0177 a}{0.0177}

Solution steps

0.0177 = \frac{lo g _{10} ( 0.29 )}{( a - x )}

Simplify

\frac{lo g _{10} ( 0.29 )}{( a - x )} : \frac{lo g _{10} ( 0.29 )}{a - x}

0.0177 = \frac{lo g _{10} ( 0.29 )}{a - x}

Multiply both sides by

a - x

0.0177 (a - x) = lo g_{10} (0.29)

Divide both sides by

0.0177

a - x = \frac{lo g _{10} ( 0.29 )}{0.0177}

Move

a

to the right side

- x = \frac{lo g _{10} ( 0.29 )}{0.0177} - a

Divide both sides by

- 1

x = - \frac{lo g _{10} ( 0.29 ) - 0.0177 a}{0.0177}

\frac{5}{x} - \frac{1}{( x + 2 )} = 1

52 = \frac{n}{2 [ 2 ( - 8 ) + ( n - 1 ) ( - 2 ) ]}

\frac{( x ^{2} - 2 x - 2 )}{( ( x ^{2} + 2 ) ^{2} )} = 0

5.4 = \frac{x ^{2}}{( ( 2 - x ) ^{2} )}

\frac{- ( 28 q ^{2} + 57 q - 144 ) \cdot 1}{( 2 q ^{3} )} = q - 6

What is the answer to 0.0177=(log_{10}(0.29))/((a-x)) ?
The answer to 0.0177=(log_{10}(0.29))/((a-x)) is x=-(log_{10}(0.29)-0.0177a)/(0.0177)