What is the answer to solvefor a, a/b+c+b/c+a+c/a+b=0 ?

The answer to solvefor a, a/b+c+b/c+a+c/a+b=0 is

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solvefor a, a/b+c+b/c+a+c/a+b=0

solve for

a, \frac{a}{b} + c + \frac{b}{c} + a + \frac{c}{a} + b = 0

a = \frac{- b c ^{2} - b ^{2} - b ^{2} c + ( b c ^{2} + b ^{2} + b ^{2} c ) ^{2} - 4 b c ^{2} ( c + b c )}{2 ( c + b c )}, a = \frac{- b c ^{2} - b ^{2} - b ^{2} c - ( b c ^{2} + b ^{2} + b ^{2} c ) ^{2} - 4 b c ^{2} ( c + b c )}{2 ( c + b c )}; c + b c \neq = 0

Solution steps

\frac{a}{b} + c + \frac{b}{c} + a + \frac{c}{a} + b = 0

Multiply by LCM

a^{2} c + ab c^{2} + a b^{2} + a^{2} b c + b c^{2} + a b^{2} c = 0

Solve

a^{2} c + ab c^{2} + a b^{2} + a^{2} b c + b c^{2} + a b^{2} c = 0 : a = \frac{- b c ^{2} - b ^{2} - b ^{2} c + ( b c ^{2} + b ^{2} + b ^{2} c ) ^{2} - 4 b c ^{2} ( c + b c )}{2 ( c + b c )}, a = \frac{- b c ^{2} - b ^{2} - b ^{2} c - ( b c ^{2} + b ^{2} + b ^{2} c ) ^{2} - 4 b c ^{2} ( c + b c )}{2 ( c + b c )}; c + b c \neq = 0

a = \frac{- b c ^{2} - b ^{2} - b ^{2} c + ( b c ^{2} + b ^{2} + b ^{2} c ) ^{2} - 4 b c ^{2} ( c + b c )}{2 ( c + b c )}, a = \frac{- b c ^{2} - b ^{2} - b ^{2} c - ( b c ^{2} + b ^{2} + b ^{2} c ) ^{2} - 4 b c ^{2} ( c + b c )}{2 ( c + b c )}; c + b c \neq = 0

\frac{( x - 1 )}{( x + 1 )} + \frac{( x + 1 )}{( x - 1 )} = \frac{5}{2}

\frac{( x - 5 )}{( x + 3 ) - 1} = \frac{( 5 x - 2 )}{( 9 - x ^{2} )}

x, \frac{3}{x} + \frac{3}{y} = 6

l \cdot n = \frac{12 \cdot 14}{h \cdot 0}

(\frac{x + 1 + 1}{x})^{2} = (\frac{x - 1 - 1}{x})^{2}

What is the answer to solvefor a, a/b+c+b/c+a+c/a+b=0 ?
The answer to solvefor a, a/b+c+b/c+a+c/a+b=0 is