What is the answer to ((x+1)/x)^2+((1-1)/x)^2=1 ?

The answer to ((x+1)/x)^2+((1-1)/x)^2=1 is x=-1/2

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((x+1)/x)^2+((1-1)/x)^2=1

(\frac{x + 1}{x})^{2} + (\frac{1 - 1}{x})^{2} = 1

x = - \frac{1}{2}

Decimal Notation

x = - 0.5

Solution steps

(\frac{x + 1}{x})^{2} + (\frac{1 - 1}{x})^{2} = 1

Simplify

\frac{( x + 1 ) ^{2}}{x ^{2}} + 0 = 1

Multiply both sides by

x^{2}

(x + 1)^{2} = x^{2}

Expand

(x + 1)^{2} : x^{2} + 2 x + 1

x^{2} + 2 x + 1 = x^{2}

Move

1

to the right side

x^{2} + 2 x = x^{2} - 1

Move

x^{2}

to the left side

2 x = - 1

Divide both sides by

2

x = - \frac{1}{2}

Verify Solutions

Find undefined (singularity) points:

x = 0

Combine undefined points with solutions:

x = - \frac{1}{2}

\frac{( n + 1 ) !}{( n - 1 ) !} = 20

t, s = \frac{d}{( t - t _{0} )}

\frac{3}{( x + \frac{1}{2} ) - x ^{2} + 3 x} = \frac{6}{( 2 x + 1 )} + x^{2} - 2

x, f (x - 3) = \frac{( x ^{2} - 9 )}{( x + 1 )}

80 x^{- 2} = 6 x^{- 1} + 2

What is the answer to ((x+1)/x)^2+((1-1)/x)^2=1 ?
The answer to ((x+1)/x)^2+((1-1)/x)^2=1 is x=-1/2
Solve for x: ((x+1)/x)^2+((1-1)/x)^2=1
The solution is x=-1/2