What is the answer to solvefor x, 1/x+1/y+1/z =1 ?

The answer to solvefor x, 1/x+1/y+1/z =1 is x=-(yz)/(z+y-yz);\quad y\ne-z/(1-z)

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solvefor x, 1/x+1/y+1/z =1

solve for

x, \frac{1}{x} + \frac{1}{y} + \frac{1}{z} = 1

x = - \frac{yz}{z + y - yz}; y \neq = - \frac{z}{1 - z}

Solution steps

\frac{1}{x} + \frac{1}{y} + \frac{1}{z} = 1

Multiply by LCM

yz + x z + x y = x yz

Move

yz

to the right side

x z + x y = x yz - yz

Move

x yz

to the left side

x z + x y - x yz = - yz

Factor

x z + x y - x yz : x (z + y - yz)

x (z + y - yz) = - yz

Divide both sides by

z + y - yz; y \neq = - \frac{z}{1 - z}

x = - \frac{yz}{z + y - yz}; y \neq = - \frac{z}{1 - z}

\frac{( x + 1 )}{( 3 x - 1 )} = (\frac{20}{50})

x^{2} + [\frac{x}{( x + 1 )}]^{2} = 3

\frac{( ( x - 2 ) ^{2} )}{7} = \frac{49}{( x - 2 )}

\frac{x + 1}{x} = \frac{a + 1}{a}

\frac{x ^{2} + 1}{x ^{2}} = 2

What is the answer to solvefor x, 1/x+1/y+1/z =1 ?
The answer to solvefor x, 1/x+1/y+1/z =1 is x=-(yz)/(z+y-yz);\quad y\ne-z/(1-z)