What is the answer to k=((a*v^2))/((b+x^2)) ?

The answer to k=((a*v^2))/((b+x^2)) is x=sqrt((av^2)/k-b),x=-sqrt((av^2)/k-b);\quad k\ne 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

k=((a*v^2))/((b+x^2))

k = \frac{( a \cdot v ^{2} )}{( b + x ^{2} )}

x = \frac{a v ^{2}}{k} - b, x = - \frac{a v ^{2}}{k} - b; k \neq = 0

Solution steps

k = \frac{( a v ^{2} )}{( b + x ^{2} )}

Simplify

\frac{( a v ^{2} )}{( b + x ^{2} )} : \frac{a v ^{2}}{b + x ^{2}}

k = \frac{a v ^{2}}{b + x ^{2}}

Multiply both sides by

b + x^{2}

k (b + x^{2}) = a v^{2}

Solve

k (b + x^{2}) = a v^{2} : x = \frac{a v ^{2}}{k} - b, x = - \frac{a v ^{2}}{k} - b; k \neq = 0

x = \frac{a v ^{2}}{k} - b, x = - \frac{a v ^{2}}{k} - b; k \neq = 0

\frac{2 x + 1}{3 x + 2} = 2

a, \frac{1}{a} + \frac{1}{b} + \frac{1}{c} = \frac{29}{72}

m^{- 2} = \frac{1}{9}

\frac{33}{4 + x} = 4

f, \frac{1}{f} = \frac{1}{p} + \frac{1}{q}

What is the answer to k=((a*v^2))/((b+x^2)) ?
The answer to k=((a*v^2))/((b+x^2)) is x=sqrt((av^2)/k-b),x=-sqrt((av^2)/k-b);\quad k\ne 0