What is the answer to (3x-1)^{-1}= 1/((3x-1)) ?

The answer to (3x-1)^{-1}= 1/((3x-1)) is x\ne 1/3

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(3x-1)^{-1}= 1/((3x-1))

(3 x - 1)^{- 1} = \frac{1}{( 3 x - 1 )}

x \neq = \frac{1}{3}

Solution steps

(3 x - 1)^{- 1} = \frac{1}{( 3 x - 1 )}

Refine

\frac{1}{3 x - 1} = \frac{1}{3 x - 1}

Subtract

\frac{1}{3 x - 1}

from both sides

\frac{1}{3 x - 1} - \frac{1}{3 x - 1} = \frac{1}{3 x - 1} - \frac{1}{3 x - 1}

Simplify

0 = 0

Both sides are equal

True for all x

Verify Solutions

Find undefined (singularity) points:

x = \frac{1}{3}

Since the equation is undefined for:

\frac{1}{3}

x \neq = \frac{1}{3}

\frac{500}{( 1 + r ) ^{10}} = 100

\frac{( x + 3 )}{( x + 4 )} = \frac{( x ^{2} - 1 )}{2}

1.2 (x) = \frac{6}{52 x - x}

9 + x^{- 4} = 10 x^{- 2}

\frac{100 x - 10000}{x ^{2}} = 0

What is the answer to (3x-1)^{-1}= 1/((3x-1)) ?
The answer to (3x-1)^{-1}= 1/((3x-1)) is x\ne 1/3
Solve for x: (3x-1)^{-1}= 1/((3x-1))
The solution is x\ne 1/3