What is the answer to 25+20n+4n^2= 8/((2n+5)) ?

The answer to 25+20n+4n^2= 8/((2n+5)) is n=-3/2 ,n=-3+i(sqrt(3))/2 ,n=-3-i(sqrt(3))/2

Solve for n: 25+20n+4n^2= 8/((2n+5))

The solution is n=-3/2 ,n=-3+i(sqrt(3))/2 ,n=-3-i(sqrt(3))/2

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25 + 20 n + 4 n^{2} = \frac{8}{( 2 n + 5 )}

n = - \frac{3}{2}, n = - 3 + i \frac{3}{2}, n = - 3 - i \frac{3}{2}

Solution steps

25 + 20 n + 4 n^{2} = \frac{8}{( 2 n + 5 )}

Simplify

\frac{8}{( 2 n + 5 )} : \frac{8}{2 n + 5}

25 + 20 n + 4 n^{2} = \frac{8}{2 n + 5}

Multiply both sides by

2 n + 5

25 (2 n + 5) + 20 n (2 n + 5) + 4 n^{2} (2 n + 5) = 8

Solve

25 (2 n + 5) + 20 n (2 n + 5) + 4 n^{2} (2 n + 5) = 8 : n = - \frac{3}{2}, n = - 3 + i \frac{3}{2}, n = - 3 - i \frac{3}{2}

n = - \frac{3}{2}, n = - 3 + i \frac{3}{2}, n = - 3 - i \frac{3}{2}

Verify Solutions

Find undefined (singularity) points:

n = - \frac{5}{2}

Combine undefined points with solutions:

n = - \frac{3}{2}, n = - 3 + i \frac{3}{2}, n = - 3 - i \frac{3}{2}

\frac{( 7 y + 4 )}{( y + 2 )} = \frac{- 4}{3}

\frac{\frac{7}{12}}{y} = \frac{1}{2}

\frac{1}{5 \cdot x \cdot ( - \frac{2}{3} ) \cdot x} = \frac{9}{7} - x

\frac{( x - 1 )}{( x - 2 )} - \frac{( x - 3 )}{( x - 4 )} = - \frac{2}{15}

0.1 = \frac{0.4}{n}

What is the answer to 25+20n+4n^2= 8/((2n+5)) ?
The answer to 25+20n+4n^2= 8/((2n+5)) is n=-3/2 ,n=-3+i(sqrt(3))/2 ,n=-3-i(sqrt(3))/2
Solve for n: 25+20n+4n^2= 8/((2n+5))
The solution is n=-3/2 ,n=-3+i(sqrt(3))/2 ,n=-3-i(sqrt(3))/2