What is the answer to 2/(3(x+1/5))= 3/4 (x-6/3) ?

The answer to 2/(3(x+1/5))= 3/4 (x-6/3) is x=(27+sqrt(1889))/(30),x=(27-sqrt(1889))/(30)

Solve for x: 2/(3(x+1/5))= 3/4 (x-6/3)

The solution is x=(27+sqrt(1889))/(30),x=(27-sqrt(1889))/(30)

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\frac{2}{3 ( x + \frac{1}{5} )} = \frac{3}{4} (x - \frac{6}{3})

x = \frac{27 + 1889}{30}, x = \frac{27 - 1889}{30}

Decimal Notation

x = 2.34875 \dots, x = - 0.54875 \dots

Solution steps

\frac{2}{3 ( x + \frac{1}{5} )} = \frac{3}{4} (x - \frac{6}{3})

Multiply by LCM

40 = 9 (x - 2) (5 x + 1)

Solve

40 = 9 (x - 2) (5 x + 1) : x = \frac{27 + 1889}{30}, x = \frac{27 - 1889}{30}

x = \frac{27 + 1889}{30}, x = \frac{27 - 1889}{30}

Verify Solutions

Find undefined (singularity) points:

x = - \frac{1}{5}

Combine undefined points with solutions:

x = \frac{27 + 1889}{30}, x = \frac{27 - 1889}{30}

\frac{a}{b} = \frac{( 2 x )}{( x - 4 )}

\frac{n !}{( n - 2 ) !} = 30

\frac{x + 1}{2 x + 3} = \frac{3}{8}

\frac{( 2 x - 1 )}{( x + 2 )} + \frac{( x + 2 )}{( 2 x - 1 )} = \frac{10}{3}

\frac{( x + 5 ) !}{( x + 4 ) !} = 9

What is the answer to 2/(3(x+1/5))= 3/4 (x-6/3) ?
The answer to 2/(3(x+1/5))= 3/4 (x-6/3) is x=(27+sqrt(1889))/(30),x=(27-sqrt(1889))/(30)
Solve for x: 2/(3(x+1/5))= 3/4 (x-6/3)
The solution is x=(27+sqrt(1889))/(30),x=(27-sqrt(1889))/(30)