What is the answer to (y^2-5}{3*y}=\frac{-1)/3 ?

The answer to (y^2-5}{3*y}=\frac{-1)/3 is y=(-1+sqrt(21))/2 ,y=-(1+sqrt(21))/2

Solve for y: (y^2-5}{3*y}=\frac{-1)/3

The solution is y=(-1+sqrt(21))/2 ,y=-(1+sqrt(21))/2

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\frac{y ^{2} - 5}{3 \cdot y} = \frac{- 1}{3}

y = \frac{- 1 + 21}{2}, y = - \frac{1 + 21}{2}

Decimal Notation

y = 1.79128 \dots, y = - 2.79128 \dots

Solution steps

\frac{y ^{2} - 5}{3 y} = \frac{- 1}{3}

Cross multiply

(y^{2} - 5) \cdot 3 = - 3 y

Solve

(y^{2} - 5) \cdot 3 = - 3 y : y = \frac{- 1 + 21}{2}, y = - \frac{1 + 21}{2}

y = \frac{- 1 + 21}{2}, y = - \frac{1 + 21}{2}

Verify Solutions

Find undefined (singularity) points:

y = 0

Combine undefined points with solutions:

y = \frac{- 1 + 21}{2}, y = - \frac{1 + 21}{2}

\frac{3}{( x - 2 )} - \frac{2}{( x - 3 )} = \frac{4}{( x - 3 )} - \frac{3}{( x - 1 )}

(0.5)^{3} = (y)^{- 3}

x, (x) y = \frac{1}{( 2 x + 1 )}

y, \frac{1}{y} = a (x - 5)^{b}

\frac{x + 3}{x} = x^{2}

What is the answer to (y^2-5}{3*y}=\frac{-1)/3 ?
The answer to (y^2-5}{3*y}=\frac{-1)/3 is y=(-1+sqrt(21))/2 ,y=-(1+sqrt(21))/2
Solve for y: (y^2-5}{3*y}=\frac{-1)/3
The solution is y=(-1+sqrt(21))/2 ,y=-(1+sqrt(21))/2