What is the answer to 4/x+x/((x+3))= 9/((x^2+3x)) ?

The answer to 4/x+x/((x+3))= 9/((x^2+3x)) is x=-1

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4/x+x/((x+3))= 9/((x^2+3x))

\frac{4}{x} + \frac{x}{( x + 3 )} = \frac{9}{( x ^{2} + 3 x )}

x = - 1

Solution steps

\frac{4}{x} + \frac{x}{( x + 3 )} = \frac{9}{( x ^{2} + 3 x )}

Multiply by LCM

4 (x + 3) + x^{2} = 9

Solve

4 (x + 3) + x^{2} = 9 : x = - 1, x = - 3

x = - 1, x = - 3

Verify Solutions

Find undefined (singularity) points:

x = - 3, x = 0

Since the equation is undefined for:

- 3

x = - 1

\frac{( 2 x - 3 )}{( 4 x + 5 )} = \frac{1}{3}

\frac{a ^{3} ( 2 a - x )}{2 ( a - x ) ^{2}} = 3 a^{2}

\frac{x}{x} = 2 n^{2} + 1 -, 3 < n < 3

x, \frac{1}{x} + \frac{y}{3} = \frac{5}{6}

\frac{1}{y} + \frac{2}{y} = \frac{3}{y}

What is the answer to 4/x+x/((x+3))= 9/((x^2+3x)) ?
The answer to 4/x+x/((x+3))= 9/((x^2+3x)) is x=-1
Solve for x: 4/x+x/((x+3))= 9/((x^2+3x))
The solution is x=-1