What are the solutions to the equation 3x^2+10x+6=0 ?

The solutions to the equation 3x^2+10x+6=0 are x=(-5+sqrt(7))/3 ,x=-(5+sqrt(7))/3

Find the zeros of 3x^2+10x+6=0

The zeros of 3x^2+10x+6=0 are x=(-5+sqrt(7))/3 ,x=-(5+sqrt(7))/3

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3 x^{2} + 10 x + 6 = 0

x = \frac{- 5 + 7}{3}, x = - \frac{5 + 7}{3}

Decimal Notation

x = - 0.78474 \dots, x = - 2.54858 \dots

Solution steps

3 x^{2} + 10 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 3 \cdot 6}{2 \cdot 3}

1 0^{2} - 4 \cdot 3 \cdot 6 = 27

x_{1, 2} = \frac{- 10 \pm 2 7}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 10 + 2 7}{2 \cdot 3}, x_{2} = \frac{- 10 - 2 7}{2 \cdot 3}

x = \frac{- 10 + 2 7}{2 \cdot 3} : \frac{- 5 + 7}{3}

x = \frac{- 10 - 2 7}{2 \cdot 3} : - \frac{5 + 7}{3}

The solutions to the quadratic equation are:

x = \frac{- 5 + 7}{3}, x = - \frac{5 + 7}{3}

4 a^{2} - a - 5

(5 x + 2) (x + 1) = 1

3 (3)

(x - 1)^{2} = 25

- 5 \geq \frac{5 - 3 x}{2}

What are the solutions to the equation 3x^2+10x+6=0 ?
The solutions to the equation 3x^2+10x+6=0 are x=(-5+sqrt(7))/3 ,x=-(5+sqrt(7))/3
Find the zeros of 3x^2+10x+6=0
The zeros of 3x^2+10x+6=0 are x=(-5+sqrt(7))/3 ,x=-(5+sqrt(7))/3