What is the answer to (y^2-5)/(3y)=-13 ?

The answer to (y^2-5)/(3y)=-13 is y=(-39+sqrt(1541))/2 ,y=(-39-sqrt(1541))/2

Solve for y: (y^2-5)/(3y)=-13

The solution is y=(-39+sqrt(1541))/2 ,y=(-39-sqrt(1541))/2

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\frac{y ^{2} - 5}{3 y} = - 13

y = \frac{- 39 + 1541}{2}, y = \frac{- 39 - 1541}{2}

Decimal Notation

y = 0.12778 \dots, y = - 39.12778 \dots

Solution steps

\frac{y ^{2} - 5}{3 y} = - 13

Multiply both sides by

y

\frac{y ^{2} - 5}{3} = - 13 y

Solve

\frac{y ^{2} - 5}{3} = - 13 y : y = \frac{- 39 + 1541}{2}, y = \frac{- 39 - 1541}{2}

y = \frac{- 39 + 1541}{2}, y = \frac{- 39 - 1541}{2}

Verify Solutions

Find undefined (singularity) points:

y = 0

Combine undefined points with solutions:

y = \frac{- 39 + 1541}{2}, y = \frac{- 39 - 1541}{2}

x, \frac{1}{x} + \frac{3}{y} = 1

x, 3 y = \frac{( 1 + cos ( x ) )}{( 1 - cos ( x ) )}

a, 6 b = \frac{7}{( 5 - a )} (a)

\frac{6. 9 ^{1}}{x} - \frac{13. 6 ^{1}}{x} + \frac{6. 4 ^{1}}{x} = 0

\frac{x}{( x ^{2} - 5 x + 6 )} + \frac{( x ^{2} - 9 )}{( ( x - 3 ) ^{2} )} = 1

What is the answer to (y^2-5)/(3y)=-13 ?
The answer to (y^2-5)/(3y)=-13 is y=(-39+sqrt(1541))/2 ,y=(-39-sqrt(1541))/2
Solve for y: (y^2-5)/(3y)=-13
The solution is y=(-39+sqrt(1541))/2 ,y=(-39-sqrt(1541))/2