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Popular >

(1/(8-x))^2+42=((x+1/8)^2-x)/(2+x(x-1))

Solution

(\frac{1}{8 - x})^{2} + 42 = \frac{( x + \frac{1}{8} ) ^{2} - x}{2 + x ( x - 1 )}

Solution

No Solution

Solution steps

(\frac{1}{8 - x})^{2} + 42 = \frac{( x + \frac{1}{8} ) ^{2} - x}{2 + x ( x - 1 )}

Multiply by LCM

64 (x (x - 1) + 2) + 2688 (- x + 8)^{2} (x (x - 1) + 2) = (64 x^{2} - 48 x + 1) (- x + 8)^{2}

Solve

64 (x (x - 1) + 2) + 2688 (- x + 8)^{2} (x (x - 1) + 2) = (64 x^{2} - 48 x + 1) (- x + 8)^{2} :

No Solution for

x \in R

No Solution

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\frac{1}{100} = (\frac{x}{( 1 - x )})^{2}

(31)/(2-4(2x-3))= 1/(3*(3/4-6x))

\frac{31}{2 - 4 ( 2 x - 3 )} = \frac{1}{3 \cdot ( \frac{3}{4} - 6 x )}

Frequently Asked Questions (FAQ)

What is the answer to (1/(8-x))^2+42=((x+1/8)^2-x)/(2+x(x-1)) ?
The answer to (1/(8-x))^2+42=((x+1/8)^2-x)/(2+x(x-1)) is No Solution
Solve for x: (1/(8-x))^2+42=((x+1/8)^2-x)/(2+x(x-1))
The solution is No Solution