What is the answer to solvefor a, 1/a+1/b+1/c = 37/48 ?

The answer to solvefor a, 1/a+1/b+1/c = 37/48 is a=-(48bc)/(48c+48b-37bc);\quad b\ne-(48c)/(48-37c)

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solvefor a, 1/a+1/b+1/c = 37/48

solve for

a, \frac{1}{a} + \frac{1}{b} + \frac{1}{c} = \frac{37}{48}

a = - \frac{48 b c}{48 c + 48 b - 37 b c}; b \neq = - \frac{48 c}{48 - 37 c}

Solution steps

\frac{1}{a} + \frac{1}{b} + \frac{1}{c} = \frac{37}{48}

Multiply by LCM

48 b c + 48 a c + 48 ab = 37 ab c

Move

48 b c

to the right side

48 a c + 48 ab = 37 ab c - 48 b c

Move

37 ab c

to the left side

48 a c + 48 ab - 37 ab c = - 48 b c

Factor

48 a c + 48 ab - 37 ab c : a (48 c + 48 b - 37 b c)

a (48 c + 48 b - 37 b c) = - 48 b c

Divide both sides by

48 c + 48 b - 37 b c; b \neq = - \frac{48 c}{48 - 37 c}

a = - \frac{48 b c}{48 c + 48 b - 37 b c}; b \neq = - \frac{48 c}{48 - 37 c}

\frac{1}{2 \cdot y ^{2}} = 7 y - 12

9 = \frac{v + 4}{v + 12}

x, g = x + f \frac{( x )}{x} \cdot 3

b, a = \frac{1}{( b - c )}

x = \frac{lo g _{10} ( 109 )}{x}

What is the answer to solvefor a, 1/a+1/b+1/c = 37/48 ?
The answer to solvefor a, 1/a+1/b+1/c = 37/48 is a=-(48bc)/(48c+48b-37bc);\quad b\ne-(48c)/(48-37c)