What is the answer to solvefor x, 1/((2x))+1/((3y))=2 ?

The answer to solvefor x, 1/((2x))+1/((3y))=2 is x=-(3y)/(2(1-6y));\quad y\ne 1/6

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solvefor x, 1/((2x))+1/((3y))=2

solve for

x, \frac{1}{( 2 x )} + \frac{1}{( 3 y )} = 2

x = - \frac{3 y}{2 ( 1 - 6 y )}; y \neq = \frac{1}{6}

Solution steps

\frac{1}{( 2 x )} + \frac{1}{( 3 y )} = 2

Multiply by LCM

3 y + 2 x = 12 x y

Move

3 y

to the right side

2 x = 12 x y - 3 y

Move

12 x y

to the left side

2 x - 12 x y = - 3 y

Factor

2 x - 12 x y : 2 x (1 - 6 y)

2 x (1 - 6 y) = - 3 y

Divide both sides by

2 (1 - 6 y); y \neq = \frac{1}{6}

x = - \frac{3 y}{2 ( 1 - 6 y )}; y \neq = \frac{1}{6}

\frac{\frac{9}{5}}{x} = \frac{( \frac{3}{2} + \frac{1}{4} )}{( 1 + \frac{7}{9} )}

\frac{a}{x - 51} = 3

1 \frac{( x - 2 )}{( x + 2 )} + \frac{( x + 2 )}{( x - 2 )} = 4

\frac{- 40}{x + 2} = \frac{- 30}{x}

\frac{( 4 b ^{2} - 2 b )}{( 10 b - 5 )} = \frac{10}{1}

What is the answer to solvefor x, 1/((2x))+1/((3y))=2 ?
The answer to solvefor x, 1/((2x))+1/((3y))=2 is x=-(3y)/(2(1-6y));\quad y\ne 1/6