What are the solutions to the equation 7x^2-13x-2=0 ?

The solutions to the equation 7x^2-13x-2=0 are x=2,x=-1/7

Find the zeros of 7x^2-13x-2=0

The zeros of 7x^2-13x-2=0 are x=2,x=-1/7

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7 x^{2} - 13 x - 2 = 0

x = 2, x = - \frac{1}{7}

Solution steps

7 x^{2} - 13 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 \cdot 7 ( - 2 )}{2 \cdot 7}

(- 13)^{2} - 4 \cdot 7 (- 2) = 15

x_{1, 2} = \frac{- ( - 13 ) \pm 15}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- ( - 13 ) + 15}{2 \cdot 7}, x_{2} = \frac{- ( - 13 ) - 15}{2 \cdot 7}

x = \frac{- ( - 13 ) + 15}{2 \cdot 7} : 2

x = \frac{- ( - 13 ) - 15}{2 \cdot 7} : - \frac{1}{7}

The solutions to the quadratic equation are:

x = 2, x = - \frac{1}{7}

12 a b^{3} + 20 b

16 x y^{5} m - 6 x y^{4} m + 42 x y^{3} m - 5 x y^{2} m

\frac{1}{2} + 2

- 16 - 8 r \geq 0

3 t^{2} - 18 t + 15 = 0

What are the solutions to the equation 7x^2-13x-2=0 ?
The solutions to the equation 7x^2-13x-2=0 are x=2,x=-1/7
Find the zeros of 7x^2-13x-2=0
The zeros of 7x^2-13x-2=0 are x=2,x=-1/7