What is the answer to ((1+x^4+x^8))/(x^4)=4 ?

The answer to ((1+x^4+x^8))/(x^4)=4 is

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((1+x^4+x^8))/(x^4)=4

\frac{( 1 + x ^{4} + x ^{8} )}{x ^{4}} = 4

x = \frac{3 + 5}{2}, x = - \frac{3 + 5}{2}, x = - \frac{3 + 5}{2}, x = - - \frac{3 + 5}{2}, x = \frac{3 - 5}{2}, x = - \frac{3 - 5}{2}, x = - \frac{3 - 5}{2}, x = - - \frac{3 - 5}{2}

Solution steps

\frac{( 1 + x ^{4} + x ^{8} )}{x ^{4}} = 4

Simplify

\frac{( 1 + x ^{4} + x ^{8} )}{x ^{4}} : \frac{1 + x ^{4} + x ^{8}}{x ^{4}}

\frac{1 + x ^{4} + x ^{8}}{x ^{4}} = 4

Multiply both sides by

x^{4}

1 + x^{4} + x^{8} = 4 x^{4}

Solve

1 + x^{4} + x^{8} = 4 x^{4} : x = \frac{3 + 5}{2}, x = - \frac{3 + 5}{2}, x = - \frac{3 + 5}{2}, x = - - \frac{3 + 5}{2}, x = \frac{3 - 5}{2}, x = - \frac{3 - 5}{2}, x = - \frac{3 - 5}{2}, x = - - \frac{3 - 5}{2}

x = \frac{3 + 5}{2}, x = - \frac{3 + 5}{2}, x = - \frac{3 + 5}{2}, x = - - \frac{3 + 5}{2}, x = \frac{3 - 5}{2}, x = - \frac{3 - 5}{2}, x = - \frac{3 - 5}{2}, x = - - \frac{3 - 5}{2}

Verify Solutions

Find undefined (singularity) points:

x = 0

Combine undefined points with solutions:

x = \frac{3 + 5}{2}, x = - \frac{3 + 5}{2}, x = - \frac{3 + 5}{2}, x = - - \frac{3 + 5}{2}, x = \frac{3 - 5}{2}, x = - \frac{3 - 5}{2}, x = - \frac{3 - 5}{2}, x = - - \frac{3 - 5}{2}

\frac{2 ( x + 1 )}{3 + 4 ( x - 2 )} = \frac{x}{2 + 5}

\frac{3 x - 2}{x} = \frac{59 x ^{2} - 4}{x ^{2}}

(\frac{x + 1}{x})^{2} - 2 (\frac{x - 1}{x + 4}) - 11 = 0

\frac{21}{2 \cdot x} = \frac{331}{3}

x - 5 = \frac{2}{x}

What is the answer to ((1+x^4+x^8))/(x^4)=4 ?
The answer to ((1+x^4+x^8))/(x^4)=4 is
Solve for x: ((1+x^4+x^8))/(x^4)=4
The solution is