What is the answer to solvefor x,h(x^2)= 4/((x^2+5)) ?

The answer to solvefor x,h(x^2)= 4/((x^2+5)) is

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solvefor x,h(x^2)= 4/((x^2+5))

solve for

x, h (x^{2}) = \frac{4}{( x ^{2} + 5 )}

x = \frac{- 5 h + 25 h ^{2} + 16 h}{2 h}, x = - \frac{- 5 h + 25 h ^{2} + 16 h}{2 h}, x = \frac{- 5 h - 25 h ^{2} + 16 h}{2 h}, x = - \frac{- 5 h - 25 h ^{2} + 16 h}{2 h}

Solution steps

h (x^{2}) = \frac{4}{( x ^{2} + 5 )}

Simplify

\frac{4}{( x ^{2} + 5 )} : \frac{4}{x ^{2} + 5}

h x^{2} = \frac{4}{x ^{2} + 5}

Multiply both sides by

x^{2} + 5

h x^{2} (x^{2} + 5) = 4

Solve

h x^{2} (x^{2} + 5) = 4 : x = \frac{- 5 h + 25 h ^{2} + 16 h}{2 h}, x = - \frac{- 5 h + 25 h ^{2} + 16 h}{2 h}, x = \frac{- 5 h - 25 h ^{2} + 16 h}{2 h}, x = - \frac{- 5 h - 25 h ^{2} + 16 h}{2 h}

x = \frac{- 5 h + 25 h ^{2} + 16 h}{2 h}, x = - \frac{- 5 h + 25 h ^{2} + 16 h}{2 h}, x = \frac{- 5 h - 25 h ^{2} + 16 h}{2 h}, x = - \frac{- 5 h - 25 h ^{2} + 16 h}{2 h}

\frac{31}{16 - ( \frac{1}{3} x - 0.75 ) ^{2}} = \frac{3}{8}

3 x^{2} - 1 = \frac{1}{5 ( 1 - x )}

\frac{3 x - 5}{x - 5} = \frac{2}{x + 5}

z, w = - \frac{z}{( z + 2 )} \frac{1}{2} (z - 12)

0.25 = \frac{117}{( 58.5 \cdot x )}

What is the answer to solvefor x,h(x^2)= 4/((x^2+5)) ?
The answer to solvefor x,h(x^2)= 4/((x^2+5)) is