What is the answer to 0= 1/(2x^2) ?

The answer to 0= 1/(2x^2) is No Solution

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0= 1/(2x^2)

0 = \frac{1}{2 x ^{2}}

No Solution

Solution steps

0 = \frac{1}{2 x ^{2}}

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

0 = 1

The sides are not equal

No Solution

2 \frac{x}{x} - 4 + \frac{1}{x} - 2 + \frac{2}{x ^{2}} - 6 x + 8 = 0

\frac{6 x}{9 x + 16} = 12

b, a = \frac{1}{2} h (\frac{a}{b})

y^{^{''}} (t) + y^{^{'}} (t) - 2 y = \frac{0}{y} (0) = 4, y^{^{'}} (0) = - 5

a = x + \frac{1}{x} e n, 1 < x < 5