What is the answer to [(x+1)/x ]^2=(4+3)/(2*[x-1/x ]) ?

The answer to [(x+1)/x ]^2=(4+3)/(2*[x-1/x ]) is x\approx-0.42571…,x\approx 2.07589…

Solve for x: [(x+1)/x ]^2=(4+3)/(2*[x-1/x ])

The solution is x\approx-0.42571…,x\approx 2.07589…

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[\frac{x + 1}{x}]^{2} = \frac{4 + 3}{2 \cdot [ x - \frac{1}{x} ]}

x \approx - 0.42571 \dots, x \approx 2.07589 \dots

Solution steps

[\frac{x + 1}{x}]^{2} = \frac{4 + 3}{2 [ x - \frac{1}{x} ]}

Cross multiply

(x + 1)^{2} \cdot 2 (x^{2} - 1) = 7 x^{3}

Solve

(x + 1)^{2} \cdot 2 (x^{2} - 1) = 7 x^{3} : x \approx - 0.42571 \dots, x \approx 2.07589 \dots

x \approx - 0.42571 \dots, x \approx 2.07589 \dots

Verify Solutions

Find undefined (singularity) points:

x = 0, x = - 1, x = 1

Combine undefined points with solutions:

x \approx - 0.42571 \dots, x \approx 2.07589 \dots

\frac{61}{2} = \frac{11}{2 + n}

\frac{4 x}{x + 1} = \frac{10}{3}

\frac{( 11 ( 2 + x ) - 5 ( x + 1 ) )}{( 3 - 7 x )} = 2

ln (0.9) = \frac{- 36 \cdot 1 0 ^{10}}{x}

x^{2} + (\frac{- 3}{4 \cdot x})^{2} = 25

What is the answer to [(x+1)/x ]^2=(4+3)/(2*[x-1/x ]) ?
The answer to [(x+1)/x ]^2=(4+3)/(2*[x-1/x ]) is x\approx-0.42571…,x\approx 2.07589…
Solve for x: [(x+1)/x ]^2=(4+3)/(2*[x-1/x ])
The solution is x\approx-0.42571…,x\approx 2.07589…