What is the answer to 1/(2x^2)=5 ?

The answer to 1/(2x^2)=5 is x= 1/(sqrt(10)),x=-1/(sqrt(10))

Solve for x: 1/(2x^2)=5

The solution is x= 1/(sqrt(10)),x=-1/(sqrt(10))

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\frac{1}{2 x ^{2}} = 5

x = \frac{1}{10}, x = - \frac{1}{10}

Decimal Notation

x = 0.31622 \dots, x = - 0.31622 \dots

Solution steps

\frac{1}{2 x ^{2}} = 5

Multiply both sides by

x^{2}

\frac{1}{2} = 5 x^{2}

Solve

\frac{1}{2} = 5 x^{2} : x = \frac{1}{10}, x = - \frac{1}{10}

x = \frac{1}{10}, x = - \frac{1}{10}

Verify Solutions

Find undefined (singularity) points:

x = 0

Combine undefined points with solutions:

x = \frac{1}{10}, x = - \frac{1}{10}

f, \frac{1}{f} = (n - 1) (\frac{1}{r} 1 + \frac{1}{r ^{2}})

1 - \frac{1}{( x + 2 )} - \frac{1}{( 2 - x )} = \frac{( 2 x )}{( x ^{2} - 4 )}

\frac{x}{( x + 1 )} + 2 = \frac{( 2 x - 3 )}{x} + \frac{3}{( x ( x + 1 ) )}

\frac{( x - b )}{( x - a )} + \frac{( x - a )}{( b - a )} = 1

\frac{4 x + 1}{3 x} = 8

What is the answer to 1/(2x^2)=5 ?
The answer to 1/(2x^2)=5 is x= 1/(sqrt(10)),x=-1/(sqrt(10))
Solve for x: 1/(2x^2)=5
The solution is x= 1/(sqrt(10)),x=-1/(sqrt(10))