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Popular >

solvefor f, 1/f =(n-1)(1/r 1+1/(r^2))

Solution

solve for

f, \frac{1}{f} = (n - 1) (\frac{1}{r} 1 + \frac{1}{r ^{2}})

Solution

f = \frac{r ^{2}}{( r + 1 ) ( n - 1 )}; r \neq = - 1

Solution steps

\frac{1}{f} = (n - 1) (\frac{1}{r} \cdot 1 + \frac{1}{r ^{2}})

Multiply both sides by

f

1 = f (n - 1) (\frac{1}{r} + \frac{1}{r ^{2}})

Switch sides

f (n - 1) (\frac{1}{r} + \frac{1}{r ^{2}}) = 1

Divide both sides by

(n - 1) (\frac{1}{r} + \frac{1}{r ^{2}}); r \neq = - 1

f = \frac{r ^{2}}{( r + 1 ) ( n - 1 )}; r \neq = - 1

Popular Examples

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x/((x+1))+2=((2x-3))/x+3/((x(x+1)))

\frac{x}{( x + 1 )} + 2 = \frac{( 2 x - 3 )}{x} + \frac{3}{( x ( x + 1 ) )}

((x-b))/((x-a))+((x-a))/((b-a))=1

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\frac{4 x + 1}{3 x} = 8

(8x^3)/(2*x^{-5)}=4x^8

\frac{8 x ^{3}}{2 \cdot x ^{- 5}} = 4 x^{8}

Frequently Asked Questions (FAQ)

What is the answer to solvefor f, 1/f =(n-1)(1/r 1+1/(r^2)) ?
The answer to solvefor f, 1/f =(n-1)(1/r 1+1/(r^2)) is f=(r^2)/((r+1)(n-1));\quad r\ne-1