What is the answer to (5x^2+1)/((x^2)-5(x+1/x)+8)=0 ?

The answer to (5x^2+1)/((x^2)-5(x+1/x)+8)=0 is x= 1/(sqrt(5))i,x=-1/(sqrt(5))i

Solve for x: (5x^2+1)/((x^2)-5(x+1/x)+8)=0

The solution is x= 1/(sqrt(5))i,x=-1/(sqrt(5))i

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\frac{5 x ^{2} + 1}{( x ^{2} ) - 5 ( x + \frac{1}{x} ) + 8} = 0

x = \frac{1}{5} i, x = - \frac{1}{5} i

Solution steps

\frac{5 x ^{2} + 1}{( x ^{2} ) - 5 ( x + \frac{1}{x} ) + 8} = 0

Simplify

\frac{5 x ^{2} + 1}{( x ^{2} ) - 5 ( x + \frac{1}{x} ) + 8} : \frac{5 x ^{2} + 1}{x ^{2} - 5 ( x + \frac{1}{x} ) + 8}

\frac{5 x ^{2} + 1}{x ^{2} - 5 ( x + \frac{1}{x} ) + 8} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

5 x^{2} + 1 = 0

Solve

5 x^{2} + 1 = 0 : x = \frac{1}{5} i, x = - \frac{1}{5} i

x = \frac{1}{5} i, x = - \frac{1}{5} i

\frac{270}{( x - 12 )} - \frac{270}{x} = \frac{3}{4}

\frac{( 3 a + b )}{s} = 7

l (1) = \frac{1}{s}

\frac{( 3 x ^{2} - 11 )}{( x ^{2} + 3 x )} = 3

\frac{x ^{2} + 1}{x ^{2}} = \frac{41}{4}

What is the answer to (5x^2+1)/((x^2)-5(x+1/x)+8)=0 ?
The answer to (5x^2+1)/((x^2)-5(x+1/x)+8)=0 is x= 1/(sqrt(5))i,x=-1/(sqrt(5))i
Solve for x: (5x^2+1)/((x^2)-5(x+1/x)+8)=0
The solution is x= 1/(sqrt(5))i,x=-1/(sqrt(5))i