What is the answer to solvefor v, 1/v+n/r =((n-1))/r ?

The answer to solvefor v, 1/v+n/r =((n-1))/r is v=-r

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solvefor v, 1/v+n/r =((n-1))/r

solve for

v, \frac{1}{v} + \frac{n}{r} = \frac{( n - 1 )}{r}

v = - r

Solution steps

\frac{1}{v} + \frac{n}{r} = \frac{( n - 1 )}{r}

Multiply by LCM

r + n v = n v - v

Move

r

to the right side

n v = n v - v - r

Subtract

n v - v

from both sides

n v - (n v - v) = n v - v - r - (n v - v)

Simplify

v = - r

\frac{( x + 2 )}{( x + 3 )} = 3 x^{4}

\frac{( ∣ 2 x - 1 ∣ + 4 x )}{( 4 x + 2 )} = \frac{1}{2}

\frac{( 0.4 z - 3 )}{( 1.5 z + 9 )} = \frac{7}{5}

\frac{6 x - 2}{x} = 11

\frac{( x - 1 )}{( 2 x - 1 )} + \frac{( 2 x - 1 )}{( x - 1 )} = \frac{5}{2}

What is the answer to solvefor v, 1/v+n/r =((n-1))/r ?
The answer to solvefor v, 1/v+n/r =((n-1))/r is v=-r