What is the answer to f^{-1}(9)=2,f^{-1}(-8) ?

The answer to f^{-1}(9)=2,f^{-1}(-8) is f= 9/2

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f^{-1}(9)=2,f^{-1}(-8)

f^{- 1} (9) = 2, f^{- 1} (- 8)

f = \frac{9}{2}

Decimal Notation

f = 4.5

Solution steps

f^{- 1} (9) = 2

Refine

\frac{9}{f} = 2

Multiply both sides by

f

9 = 2 f

Switch sides

2 f = 9

Divide both sides by

2

f = \frac{9}{2}

Verify Solutions

Find undefined (singularity) points:

f = 0

Combine undefined points with solutions:

f = \frac{9}{2}

\frac{x}{( x - 2 )} - \frac{( x - 2 )}{x} = \frac{5}{2}

\frac{- 3}{( x - 2 ) ^{2}} = 0

(x + x^{2} + x^{3}) + (\frac{1}{x} + \frac{1}{( x ^{2} )} + \frac{1}{( x ^{3} )}) = 28

270 = \frac{n}{2 [ 2 x ^{10} + ( n - 1 ) 5 ]}

\frac{7}{5 \cdot ( - 7 x ^{2} + 2 ) ^{2}} = \frac{5}{7}

What is the answer to f^{-1}(9)=2,f^{-1}(-8) ?
The answer to f^{-1}(9)=2,f^{-1}(-8) is f= 9/2
Solve for f: f^{-1}(9)=2,f^{-1}(-8)
The solution is f= 9/2