What is the answer to solvefor x,f=({x})/((1+{x\))} ?

The answer to solvefor x,f=({x})/((1+{x\))} is x=-f/(f-1);\quad f\ne 1

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solvefor x,f=({x})/((1+{x\))}

solve for

x, f = \frac{{ x }}{( 1 + { x } )}

x = - \frac{f}{f - 1}; f \neq = 1

Solution steps

f = \frac{{ x }}{( 1 + { x } )}

Simplify

\frac{x}{1 + ( x )} : \frac{x}{1 + x}

f = \frac{x}{1 + x}

Multiply both sides by

1 + x

f (1 + x) = x

Expand

f (1 + x) : f + x f

f + x f = x

Move

f

to the right side

x f = x - f

Move

x

to the left side

x f - x = - f

Factor

x f - x : x (f - 1)

x (f - 1) = - f

Divide both sides by

f - 1; f \neq = 1

x = - \frac{f}{f - 1}; f \neq = 1

\frac{1}{x} - \frac{1}{( x + b )} = \frac{1}{a} - \frac{1}{( a + b )}

l, z = \frac{( 1 + l )}{( ( 3 + l ) ^{2} )}

x, \frac{1}{x} + \frac{1}{y} + \frac{1}{z} = \frac{1}{5}

x, 82 f = \frac{6}{( 2 - 4 x )}

\frac{1}{2 ( 4 - x )} = 8 - 2.5 x

What is the answer to solvefor x,f=({x})/((1+{x\))} ?
The answer to solvefor x,f=({x})/((1+{x\))} is x=-f/(f-1);\quad f\ne 1