What is the answer to ((y-1))/((y^2-1))=y+1 ?

The answer to ((y-1))/((y^2-1))=y+1 is y=0,y=-2

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((y-1))/((y^2-1))=y+1

\frac{( y - 1 )}{( y ^{2} - 1 )} = y + 1

y = 0, y = - 2

Solution steps

\frac{( y - 1 )}{( y ^{2} - 1 )} = y + 1

Simplify

\frac{y - 1}{y ^{2} - 1} : \frac{1}{y + 1}

\frac{1}{y + 1} = y + 1

Multiply both sides by

y + 1

1 = y (y + 1) + y + 1

Solve

1 = y (y + 1) + y + 1 : y = 0, y = - 2

y = 0, y = - 2

Verify Solutions

Find undefined (singularity) points:

y = 1, y = - 1

Combine undefined points with solutions:

y = 0, y = - 2

\frac{x}{2 x} = 32

\frac{1}{( a + b + c )} = \frac{1}{a} + \frac{1}{b} + \frac{1}{x}

\frac{( 5 x )}{( x - 3 )} + \frac{4}{( x + 3 )} = \frac{90}{( x ^{2} - 9 )}

∣ x ∣ = \frac{1}{x}

s, 1 + \frac{k _{c}}{( ( 2 s + 1 ) ( 5 s + 1 ) )} = 0

What is the answer to ((y-1))/((y^2-1))=y+1 ?
The answer to ((y-1))/((y^2-1))=y+1 is y=0,y=-2
Solve for y: ((y-1))/((y^2-1))=y+1
The solution is y=0,y=-2