What are the solutions to the equation 4x^2=6-5x ?

The solutions to the equation 4x^2=6-5x are x= 3/4 ,x=-2

Find the zeros of 4x^2=6-5x

The zeros of 4x^2=6-5x are x= 3/4 ,x=-2

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4 x^{2} = 6 - 5 x

x = \frac{3}{4}, x = - 2

Solution steps

4 x^{2} = 6 - 5 x

Move

5 x

to the left side

4 x^{2} + 5 x = 6

Move

6

to the left side

4 x^{2} + 5 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 4 ( - 6 )}{2 \cdot 4}

5^{2} - 4 \cdot 4 (- 6) = 11

x_{1, 2} = \frac{- 5 \pm 11}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 5 + 11}{2 \cdot 4}, x_{2} = \frac{- 5 - 11}{2 \cdot 4}

x = \frac{- 5 + 11}{2 \cdot 4} : \frac{3}{4}

x = \frac{- 5 - 11}{2 \cdot 4} : - 2

The solutions to the quadratic equation are:

x = \frac{3}{4}, x = - 2

ln (2.2)

2 x^{5} y \cdot 3 x^{2} y

- 3 < x + 2 < 11

∣ x ∣ = 1

e^{- t} \cdot e^{t}

What are the solutions to the equation 4x^2=6-5x ?
The solutions to the equation 4x^2=6-5x are x= 3/4 ,x=-2
Find the zeros of 4x^2=6-5x
The zeros of 4x^2=6-5x are x= 3/4 ,x=-2