What is the answer to 1/(3x^2(x-3)+x^2)=-9 ?

The answer to 1/(3x^2(x-3)+x^2)=-9 is x\approx-0.11538…,x\approx 0.12061…,x\approx 2.66143…

Solve for x: 1/(3x^2(x-3)+x^2)=-9

The solution is x\approx-0.11538…,x\approx 0.12061…,x\approx 2.66143…

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\frac{1}{3 x ^{2} ( x - 3 ) + x ^{2}} = - 9

x \approx - 0.11538 \dots, x \approx 0.12061 \dots, x \approx 2.66143 \dots

Solution steps

\frac{1}{3 x ^{2} ( x - 3 ) + x ^{2}} = - 9

Simplify

\frac{1}{3 x ^{2} ( x - 3 ) + x ^{2}} : \frac{1}{3 x ^{3} - 8 x ^{2}}

\frac{1}{3 x ^{3} - 8 x ^{2}} = - 9

Multiply both sides by

3 x^{3} - 8 x^{2}

1 = - 9 (3 x^{3} - 8 x^{2})

Solve

1 = - 9 (3 x^{3} - 8 x^{2}) : x \approx - 0.11538 \dots, x \approx 0.12061 \dots, x \approx 2.66143 \dots

x \approx - 0.11538 \dots, x \approx 0.12061 \dots, x \approx 2.66143 \dots

Verify Solutions

Find undefined (singularity) points:

x = 0, x = \frac{8}{3}

Combine undefined points with solutions:

x \approx - 0.11538 \dots, x \approx 0.12061 \dots, x \approx 2.66143 \dots

\frac{d}{( x + 10 )} - \frac{d}{( x - 10 )} = 4

\frac{u + 1}{u} = 2

y^{16} = \frac{- 4}{7 y}

0 = \frac{- x ^{3}}{( ( x + 2 ) ( x - 1 ) )}

\frac{11}{7 x + 1} = \frac{41}{2}

What is the answer to 1/(3x^2(x-3)+x^2)=-9 ?
The answer to 1/(3x^2(x-3)+x^2)=-9 is x\approx-0.11538…,x\approx 0.12061…,x\approx 2.66143…
Solve for x: 1/(3x^2(x-3)+x^2)=-9
The solution is x\approx-0.11538…,x\approx 0.12061…,x\approx 2.66143…