What is the answer to 2x^{-5}=(16)^2 ?

The answer to 2x^{-5}=(16)^2 is x= 1/(2\sqrt[5]{4)}

Solve for x: 2x^{-5}=(16)^2

The solution is x= 1/(2\sqrt[5]{4)}

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2 x^{- 5} = (16)^{2}

Decimal Notation

x = 0.37892 \dots

Solution steps

2 x^{- 5} = (16)^{2}

Refine

\frac{2}{x ^{5}} = 256

Multiply both sides by

x^{5}

2 = 256 x^{5}

Solve

Verify Solutions

Find undefined (singularity) points:

x = 0

Combine undefined points with solutions:

(\frac{x + 1}{x})^{2} = \frac{4 + 3}{2 ( x - \frac{1}{x} )}

5 \frac{x}{x - 5} + ∣ x ∣ = \frac{x ^{2}}{∣ x - 5 ∣}

\frac{3}{4 \cdot m + 2 m} = 22

\frac{1}{4 \cdot m - 7} = 2

\frac{( x - 5 )}{x} - \frac{( x - 7 )}{( x - 1 )} = \frac{5}{x}

What is the answer to 2x^{-5}=(16)^2 ?
The answer to 2x^{-5}=(16)^2 is x= 1/(2\sqrt[5]{4)}
Solve for x: 2x^{-5}=(16)^2
The solution is x= 1/(2\sqrt[5]{4)}